CSA S16 Cl. 13.4.1.1

Steel web shear capacity

Verified against CSA S16-19, 2026-09-29

Shear stress capacity of an unstiffened steel web to CSA S16 Cl. 13.4.1.1. Determine the shear stress capacity of an unstiffened structural steel web to CSA S16 Clause 13.4.1.1. The web slenderness h/w decides which of three limit states governs: shear yielding for a stocky web, inelastic shear buckling for an intermediate one, and elastic shear buckling for a slender one. The calculator reports both slenderness limits alongside the governing capacity, so the arm it used is visible rather than assumed. The factored shear resistance V_r = phi A_w F_s follows, with A_w taken as the clear web depth times its thickness.

Given

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changed from the declared value \(h\) \(\mathrm{mm}\) 50-5,000
changed from the declared value \(w\) \(\mathrm{mm}\) 3-100
changed from the declared value \(F_{y}\) \(\mathrm{MPa}\) 200-700
Fs = 231 MPa h/w = 50, shear yielding h = 500 mm w = 10 mm
The web at true proportions, and the limit state its slenderness puts it in.

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Checks

Check D/C Utilisation Result
Web reaches shear yield\(\htmlClass{sym-h_w}{h_{w}} \leq \htmlClass{sym-h_w_1}{h_{w,1}} \quad \Rightarrow \quad \htmlClass{sym-h_w}{50} \leq \htmlClass{sym-h_w_1}{54.2}\) 0.92 PASS
Web below elastic limit\(\htmlClass{sym-h_w}{h_{w}} \leq \htmlClass{sym-h_w_2}{h_{w,2}} \quad \Rightarrow \quad \htmlClass{sym-h_w}{50} \leq \htmlClass{sym-h_w_2}{76.7}\) 0.65 PASS

Results

Quantity Description Value Unit
\(\htmlClass{sym-h_w}{h_{w}}\) Web slenderness 50
\(\htmlClass{sym-h_w_1}{h_{w,1}}\) Slenderness limit for shear yielding 54.2
\(\htmlClass{sym-h_w_2}{h_{w,2}}\) Slenderness limit for inelastic buckling 76.7
\(\htmlClass{sym-F_s}{F_{s}}\) Shear stress capacity 231 \(\mathrm{MPa}\)
\(\htmlClass{sym-A_w}{A_{w}}\) Web shear area 5000 \(\mathrm{mm}^{2}\)
\(\htmlClass{sym-V_r}{V_{r}}\) Factored shear resistance 1.04 \(\mathrm{MN}\)

Derivation

S.1 \[\begin{aligned} \htmlClass{sym-h_w}{h_{w}} &= \frac{\htmlClass{sym-h}{h}}{\htmlClass{sym-w}{w}} \\ &= \frac{\htmlClass{sym-h}{500\ \mathrm{mm}}}{\htmlClass{sym-w}{10\ \mathrm{mm}}} \\ &= 50 \end{aligned}\]
S.2 \[\begin{aligned} \htmlClass{sym-root_F_y}{\mathrm{root}_{F,y}} &= \sqrt{\htmlClass{sym-F_y}{F_{y}} \cdot 1\ \mathrm{MPa}} \\ &= \sqrt{\htmlClass{sym-F_y}{350\ \mathrm{MPa}} \cdot 1\ \mathrm{MPa}} \\ &= 18.71\ \mathrm{MPa} \end{aligned}\]
S.3

Cl. 13.4.1.1 a) i)

\[\begin{aligned} \htmlClass{sym-h_w_1}{h_{w,1}} &= 1014 \cdot \frac{1\ \mathrm{MPa}}{\htmlClass{sym-root_F_y}{\mathrm{root}_{F,y}}} \\ &= 1014 \cdot \frac{1\ \mathrm{MPa}}{\htmlClass{sym-root_F_y}{18.71\ \mathrm{MPa}}} \\ &= 54.2 \end{aligned}\]
S.4

Cl. 13.4.1.1 a) ii), iii)

\[\begin{aligned} \htmlClass{sym-h_w_2}{h_{w,2}} &= 1435 \cdot \frac{1\ \mathrm{MPa}}{\htmlClass{sym-root_F_y}{\mathrm{root}_{F,y}}} \\ &= 1435 \cdot \frac{1\ \mathrm{MPa}}{\htmlClass{sym-root_F_y}{18.71\ \mathrm{MPa}}} \\ &= 76.7 \end{aligned}\]

Branch: \(h_{w} \leq h_{w,1}\) held

S.5

Cl. 13.4.1.1 a) i), shear yielding

\[\begin{aligned} \htmlClass{sym-F_s}{F_{s}} &= 0.66 \cdot \htmlClass{sym-F_y}{F_{y}} \\ &= 0.66 \cdot \htmlClass{sym-F_y}{350\ \mathrm{MPa}} \\ &= 231\ \mathrm{MPa} \end{aligned}\]
S.6

Cl. 13.4.1.1, girder form

\[\begin{aligned} \htmlClass{sym-A_w}{A_{w}} &= \htmlClass{sym-h}{h} \cdot \htmlClass{sym-w}{w} \\ &= \htmlClass{sym-h}{500\ \mathrm{mm}} \cdot \htmlClass{sym-w}{10\ \mathrm{mm}} \\ &= 5000\ \mathrm{mm}^{2} \end{aligned}\]
S.7

Cl. 13.4.1.1, phi = 0.90 per Cl. 13.1 a)

\[\begin{aligned} \htmlClass{sym-V_r}{V_{r}} &= 0.9 \cdot \htmlClass{sym-A_w}{A_{w}} \cdot \htmlClass{sym-F_s}{F_{s}} \\ &= 0.9 \cdot \htmlClass{sym-A_w}{5000\ \mathrm{mm}^{2}} \cdot \htmlClass{sym-F_s}{231\ \mathrm{MPa}} \\ &= 1.04\ \mathrm{MN} \end{aligned}\]

Questions

Why does Cl. 13.4.1.1 cover unstiffened webs only here?

Unstiffened webs only. The constants in Clause 13.4.1.1 assume a shear buckling coefficient of 5.34, which is the unstiffened value; a stiffened web's coefficient depends on the spacing of its transverse stiffeners.

What is h/w, and which F_s does it select?

The web slenderness, clear depth h over thickness w. At or below 1014 / sqrt(F_y) the web reaches shear yield and F_s = 0.66 F_y; up to 1435 / sqrt(F_y) it buckles inelastically, and beyond that elastically, with F_s falling as (w/h) squared. For 350 MPa steel the two limits are about 54 and 77.

Is F_s a factored resistance?

No. F_s is a shear stress. The factored shear resistance is V_r = phi A_w F_s, with A_w the web area h w and phi = 0.90 (Cl. 13.1). For a rolled shape the clause takes d w, so h w is slightly conservative.